x (where x is amount of faps) x 2 + 5 x 50 + 1760 (if birthday already passed, 1759 else) - xxxx (year of birth) = 3 digit number. The last two numbers of that = your current age.
IE; 0 x 2 + 5 x 50 + 1760 - 1981 = 329 = age 29.
1 gives me a 2 digit number
2 it aint close
3 still not good
x (where x is amount of faps) x 2 + 5 x 50 + 1760 (if birthday already passed, 1759 else) - xxxx (year of birth) = 3 digit number. The last two numbers of that = your current age.
IE; 0 x 2 + 5 x 50 + 1760 - 1981 = 329 = age 29.
1 gives me a 2 digit number
2 it aint close
3 still not good
This happens if you put it in completely, but you have to calculate it separately.
If you use 4, for instance:
4x2 -> 8
8 + 5 -> 13
13x50 -> 650
650 + 1760 -> 2410
2410 - 1986 = 424,
So the first number is the same as times fapping.
Quite logic, it's basically fAps times 100,
The number you use to subtract the birth year from, is 20 + faps with a 10 at the end..
So just 2010 minus birth year, with an extra number because your faps have multiplied.
It always works because of this (I hope I explain it right)
1. Multiplying any number by 2 will ALWAYS give you an even number.
2. By adding 5 you will ALWAYS get an odd number.
3. Multiplying an odd number times 50 will ALWAYS give you a number that ends with 50.
4. As only the last 2 digits count, the number "1760" (or 1759 respectively) is just a distraction. It's the 60 (or the 59) that's important. So adding this to 50 will ALWAYS give you 10 or 09 as the last digits.
5. This is important because we have the year 2010 (it ends with a 10 you see ), so substracting your birthyear will obviously give you your age.
Edit: Damn, Ninja'd
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Here's the full thing;
but isn't that a torrent ?
), so substracting your birthyear will obviously give you your age.
good one 
